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Answer 1 · 2018-02-25T09:27:55

Q = 0

W = 218.75J

$Delta$ T = 418.6K

Adiabatic process is a type of thermodynamic process which involves no heat exchange with the surroundings.

As a result Q = 0.

Work done by an ideal gas is the area bounded by PV- graph

Incase of constant pressure, the graph will be straight line.

As a result,

W= P $Delta$ V = (62.5k)(3.5 $xx$ $10^-3$ ) = 218.75J

Because the gas expanded the work done is positive.

$V/T$ = Constant

T2 = 717.6K

$Delta$ T= $T_2$ - $T_1$ = 717.6 - 299 = 418.6K