If Mere an astronaut on the moon drops a hammer from a height of 1.4 meters. How long will it take the hammer to reach the ground if the gravitational acceleration on the moon is (one sixth) of that on earth?
2 Answers
1.30 seconds.
Explanation:
Assuming the acceleration due to gravity on Earth is an exact value
This value is our new a.
But
Using formula, where h is height, t is time taken, and g is the magnitude of the acceleration,
and solving for time with algebraic manipulation we get:
Plug in our givens and get
1.3 s
Explanation:
Let acc. on the moon be g'
As acceleration due to gravity on the moon is
g'= g/6. ( where g is the acc. due to gravity on the earth)
Now, according to the second law of kinematics,
S=
Here, s=
So we have,
As g= 9.8
On simplifying we get,