How do you solve #6= 4r - 3r#?

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Answer 1 · 2018-02-24T02:59:24

#r=6#

The only thing you need to do to solve this is to combine like terms and get the variable #r# by itself.

Combining like terms would go from:

#6=4r-3r#

To:

#6=r#

Lucky enough, #r# is by itself already, so we can give the answer of:

#r=6#