How do I solve for the equation 0 ≤ x < 2π √2 tan x = 2 sin x ?

1 Answer
salamat
Feb 22, 2018

#x = pi/4, 7/4 pi#

Explanation:

#sqrt(2) tan x = 2 sin#

#tan x / sin x = 2/ sqrt(2)#

#1/cos x = sqrt (2)#

note:
#tan x /sin x = tan x -: sin x = sin x/cos x -: sin x = cancel(sin x)/cos x * 1/ cancel(sin x) = 1/cos x#

#cos x = 1/sqrt (2)#

#x = pi/4, 7/4 pi#

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