What is the maximum and minimum of y=1-3sin(2x)?

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What is the maximum and minimum of y=1-3sin(2x)?

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Answer 1 · 2018-02-20T23:05:39

Maximum: 4 (occuring at x values of $\frac{π}{4} + n \cdot π$ $pi/4 +n*pi$ )
Minimum: -2 (occuring at x values of $\frac{3 π}{4} + n \cdot π$ $(3pi)/4 +n*pi$ )

Explanation:

Reminder: sine's maximum value is 1 and minimum value is 1.
Plugging those in, you get 1-3(1) and 1-3(-1). The y values gotten out of it are: $(\frac{π}{4}, - 2)$ $(pi/4, -2)$ which is the minimum, with maximum being $(\frac{3 π}{4}, 4)$ $((3pi)/4, 4)$ which is the maximum.

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What is the maximum and minimum of y=1-3sin(2x)?

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