Question #7f767

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Question #7f767

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Answer 1 · 2018-02-20T19:35:22

Derivatives given below.

Explanation:

f(x,y)=-10sin(2x+y) + cos (x-y)

$f_{x} (x, y)$ $f_x (x,y)$ = -10 cos (2x +y) (2) - 6 sin (x-y)
= -20 cos (2x+y) - 6 sin (x-y)
$f_{y} (x, y)$ $f_y(x,y)$ = -10cos (2x+y) -6 sin (x-y) (-1)
= -10 cos (2x+y) +6 sin (x-y)

$f_{x x} (x, y)$ $f_(x x) (x,y)$ = 40 sin (2x+y)- 6 cos (x-y)

$f_{y y} (x, y)$ $f_(y y) (x,y)$ =20 sin (2x+y) - 6 cos (x-y)

$f_{x y} (x, y)$ $f_(x y) (x,y)$ =20 sin (2x+y)+6 cos (x-y)

$f_{y x} (x, y)$ $f_(y x) (x,y)$ =20 sin (2x+y)+6 cos(x-y)

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Question #7f767

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