Question #847b3

2 Answers
VNVDVI
Feb 20, 2018

C. #9x^2#

Explanation:

#(27x^3)^(2/3)#= #root(3)((27x^3)^2)#

= #root(3)#( #729x^6# )
= #root(3)(729) * root(3)x^6#
#=9x^2#

Jim G.
Feb 20, 2018

#9x^2toC#

Explanation:

#"using the "color(blue)"laws of exponents"#

#•color(white)(x)(a^mb^n)^p=a^(mp)b^(np)#

#•color(white)(x)a^(m/n)=(root(n)(a))^m#

#rArr(27x^3)^(2/3)=27^(2/3)x^((3xx2/3))=27^(2/3)x^2#

#27^(2/3)=(root(3)(27))^2=3^2=9#

#rArr(27x^3)^(2/3)=9x^2toC#

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