Question #42234

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Question #42234

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Answer 1 · 2018-02-18T20:22:43

29.8ml

Explanation:

Density of liquid oxygen = 1.141g/ $c m^{3}$ $cm^3$
Density of liquid hydrogen = 0.071 g/ $c m^{3}$ $cm^3$

Since 1ml=1 $c m^{3}$ $cm^3$ and $d e n s i t y = \frac{m a s s}{v o l u m e}$ $density = (mass)/(volume)$ we can calculate the masses of the above:
Mass oxygen $= 1.141 \times 10 = 11.41 g$ $=1.141times10=11.41g$
Mass hydrogen= $0.071 \times 50 = 3.55 g$ $0.071 times 50=3.55g$

We can calculate relative molecualr masses (I have used 1d.p. but you may wish to be more accurate)
$M r (O_{2}) = 16.0 \times 2 = 32.0$ $Mr (O_2)=16.0 times2=32.0$
$M r (H_{2}) = 1.0 \times 2 = 2.0$ $Mr (H_2)=1.0times2=2.0$

We can now work out the number of moles of each:
Moles $(O_{2}) = \frac{11.41}{32.0} = 0.357 m o l$ $(O_2)=11.41/32.0=0.357 mol$

Moles $(H_{2}) = \frac{3.55}{2.0} = 1.775 m o l$ $(H_2)=3.55/2.0=1.775 mol$

The reaction is
$2 H_{2} + O_{2} \to 2 H_{2} O$ $2H_2 +O_2 to 2H_2O$

so 2 moles $H_{2}$ $H_2$ reacts with 1 mole $O_{2}$ $O_2$
hence unreacted $H_{2}$ $H_2$ = $1.775 - (0.357 \times 2) = 1.061 m o l$ $1.775-(0.357times2)=1.061mol$

And so Mass = $1.061 \times 2 = 2.122 g$ $1.061 times 2= 2.122g$

and volume = $\frac{2.122}{0.071} = 29.9 m l$ $2.122/0.071=29.9ml$

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Question #42234

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