Determine the number of x-intercepts that appear on a graph of each function. f (x) = (x + 1)(x - 3)(x - 4) How many X-intercepts are there?

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Determine the number of x-intercepts that appear on a graph of each function. f (x) = (x + 1)(x - 3)(x - 4) How many X-intercepts are there?

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Answer 1 · 2018-02-18T03:16:14

There are $3$ $3$ $x$ $x$ -intercepts $\to (- 1, 0), (3, 0), (4, 0)$ $-> (-1,0), (3,0), (4,0)$

Explanation:

To find the $x$ $x$ -intercepts, set the $y$ $y$ value or $f (x)$ $f(x)$ equal to $0$ $0$ .

$f (x) = 0$ $f(x) = 0$

$0 = (x + 1) (x - 3) (x - 4) \leftarrow$ $0 = (x+1)(x-3)(x-4) larr$ Now set each term equal to $0$ $0$

$(x + 1) = 0 \to x = - 1$ $(x+1) = 0 -> x = -1$

$(x - 3) = 0 \to x = 3$ $(x-3) = 0 -> x = 3$

$(x - 4) = 0 \to x = 4$ $(x-4) = 0 -> x = 4$

Since the $y$ $y$ value is $0$ $0$ , with the above $x$ $x$ values, you can find the $x$ $x$ -intercept points: $(- 1, 0), (3, 0), (4, 0)$ $(-1,0), (3,0), (4,0)$ .

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Determine the number of x-intercepts that appear on a graph of each function. f (x) = (x + 1)(x - 3)(x - 4) How many X-intercepts are there?

1 Answer

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