Cot theta - tan theta/ cot theta + tan theta?

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Cot theta - tan theta/ cot theta + tan theta?

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Answer 1 · 2018-02-17T17:26:14

$\frac{cot θ - tan θ}{cot θ + tan θ}$ $(Cot theta - tan theta)/ (cot theta + tan theta$

$\Rightarrow \frac{\frac{cos θ}{sin θ} - \frac{sin θ}{cos θ}}{\frac{cos θ}{sin θ} + \frac{sin θ}{cos θ}}$ $=>(Cos theta/sintheta - sintheta/Cos theta)/ (Cos theta/sintheta+ sintheta/Cos theta$

$\Rightarrow \frac{{cos}^{2} θ - {sin}^{2} θ}{{cos}^{2} θ + {sin}^{2} θ}$ $=>(cos^2theta - sin^2theta )/(cos^2theta + sin^2theta$

$\Rightarrow \frac{cos 2 θ}{1}$ $=>(cos2theta)/1$

$= cos 2 θ$ $=cos2theta$

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Cot theta - tan theta/ cot theta + tan theta?

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