What is the standard form of $y = (3 x - 1) (7 x - 2) (x + 1)$ $y= (3x-1)(7x-2)(x+1)$ ?

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What is the standard form of $y = (3 x - 1) (7 x - 2) (x + 1)$ $y= (3x-1)(7x-2)(x+1)$ ?

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Answer 1 · 2018-02-17T08:58:08

$21 x^{3} + 20 x^{2} + x + 2$ $21x^3+20x^2+x+2$

Explanation:

Given: $y = (3 x - 1) (7 x - 2) (x + 1)$ $y=(3x-1)(7x-2)(x+1)$
First, solve $(3 x - 1)$ $(3x-1)$ and $(7 x - 1)$ $(7x-1)$ by expanding them.
$(3 x - 1) (7 x - 2)$ $(3x-1)(7x-2)$
$= 21 x^{2} - 6 x - 7 x + 2$ $=21x^2-6x-7x+2$
$= 21 x^{2} - x + 2$ $=21x^2-x+2$
Now,solve $(21 x^{2} - x + 2)$ $(21x^2-x+2)$ and $(x + 1)$ $(x+1)$ by expanding them.
$(21 x^{2} - x + 2) (x + 1)$ $(21x^2-x+2)(x+1)$
$= 21 x^{3} + 21 x^{2} - x^{2} - x + 2 x + 2$ $=21x^3+21x^2-x^2-x+2x+2$
$= 21 x^{3} + 20 x^{2} + x + 2$ $=21x^3+20x^2+x+2$

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What is the standard form of $y = (3 x - 1) (7 x - 2) (x + 1)$ $y= (3x-1)(7x-2)(x+1)$ ?

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