What is the standard form of y= (3x-1)(7x-2)(x+1) y=(3x1)(7x2)(x+1)?

1 Answer

21x^3+20x^2+x+221x3+20x2+x+2

Explanation:

Given: y=(3x-1)(7x-2)(x+1)y=(3x1)(7x2)(x+1)
First, solve (3x-1)(3x1) and (7x-1)(7x1) by expanding them.
(3x-1)(7x-2)(3x1)(7x2)
=21x^2-6x-7x+2=21x26x7x+2
=21x^2-x+2=21x2x+2
Now,solve (21x^2-x+2)(21x2x+2) and (x+1)(x+1) by expanding them.
(21x^2-x+2)(x+1)(21x2x+2)(x+1)
=21x^3+21x^2-x^2-x+2x+2=21x3+21x2x2x+2x+2
=21x^3+20x^2+x+2=21x3+20x2+x+2