How to find d/dx ?

d/dx {(1+#x^2+x^4#)^2x-3 }

1 Answer
Gav
Feb 17, 2018

#d/dx# =#(4x-6)(x^4+x^2+1)^(2x-4)+(4x^3+2x)#

Explanation:

Applying the product rule;
Bring (2x-3) down, the power minus 1. Lastly, multiply by 2 because we have to differentiate 2x-3
Next we differentiate the value of #(x^4+x^2+1)#,
So, #d/dx# = #(2x-3)(x^4+x^2+1)^((2x-3)-1)(2)+(4x^3+2x)#
#d/dx# =#(4x-6)(x^4+x^2+1)^(2x-4)+(4x^3+2x)#

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