Kinetic energy of an object is 25 j. Velocity is 5 m/s what will be its kinetic energy if velocity is doubles?

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Kinetic energy of an object is 25 j. Velocity is 5 m/s what will be its kinetic energy if velocity is doubles?

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Answer 1 · 2018-02-17T04:37:36

$100 J$ $"100 J"$

Explanation:

$KE = (\frac{1}{2}) \cdot m \cdot v^{2}$ $"KE"=(1/2)*m*v^2$

Simple explanation :

Since the KE is proportional to velocity squared, if you increase the KE by a factor of $2$ $2$ , you increase $v$ $v$ by a factor of $2^{2} = 4$ $2^2= 4$

Detailed explanation :

$25 = 0.5 \cdot m \cdot (5^{2})$ $25=0.5*m*(5^2)$

Find $m$ $m$ :

$25 = 25 \frac{m}{2}$ $25=25m/2$

$m = 2$ $m=2$

Hence the new KE:

$KE = 0.5 \cdot 2 \cdot 10^{2}$ $"KE"=0.5*2*10^2$

$KE = 100 J$ $"KE"=100 J$

Answer 2 · 2018-02-17T04:39:29

The kinetic energy of body is $100 J$ $"100 J"$ .

Explanation:

$kinetic energy = \frac{1}{2} \times m \times v^{2} = 25 J$ $"kinetic energy" =1/2 xx mxxv^2="25 J"$

$v = 5 m/s$ $v = "5 m/s"$

Let the mass of body be $m$ $m$ .

$\frac{1}{2} \times m \times v^{2} = 25$ $1/2xxmxxv^2=25$

$m \times 5^{2} = 50$ $mxx5^2=50$

$m \times 25 = 50$ $mxx 25=50$

$m = \frac{50}{25}$ $m=50/25$

or

$m = 2 kg$ $m = "2 kg"$

Now if velocity is doubled then

$v'=2 * v$

$v'=2×x5$

$v' = "10 m/s"$

The final kinetic energy $=1/2xxmxx(v')^2$

$=1/2x×2x×10^2$

$=1/2x×2x×100$

$=100J$

Answer 3 · 2018-02-17T05:56:37

$100J$

Explanation:

We know that the equation for kinetic energy is

$KE=1/2mv^2$

Here, $v=5$ , $KE=25$

$:.25=1/2*m*5^2$

$25=1/2*25*m$

$:.m=2$

So, the object's mass is $2kg$ .

If the velocity doubles, then $v=5*2=10$ , and then

$KE=1/2*10^2*2$

$KE=100J$

So, the object's kinetic energy will be $100J$ .

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Kinetic energy of an object is 25 j. Velocity is 5 m/s what will be its kinetic energy if velocity is doubles?

3 Answers

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