Question #6f5cc

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Question #6f5cc

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Answer 1 · 2018-02-16T23:32:55

An exterior angle of a regular 17-gon is $\frac{360}{17} \approx {21.1765}^{o}$ $360/17~~21.1765^o$ or $21 \frac{3}{17}$ $21 3/17$ degrees. An exterior angle of a 28-gon is $\frac{360}{28} \approx {12.857}^{o}$ $360/28~~12.857^o$ or $12 \frac{6}{7}$ $12 6/7$ degrees.

Explanation:

All convex polygon's exterior angles add up to 360 degrees.To solve for a regular n-gon's exterior angle, you take $\frac{360}{n}$ $360/n$ where $n$ $n$ is the number of sides the polygon has.

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