How do you determine the quadrant in which #-(11pi)/9# lies?

2 Answers
Daniel H.
Feb 15, 2018

The negative means you go clockwise instead of counterclockwise to graph the angle. Then...

Explanation:

Then, since #11/9# is a little more than one, it means the angle is a little more than #\pi# (or 180 degrees). Therefore, when you graph an angle moving clockwise and go past #\pi# radians, you will be in Quadrant II

sankarankalyanam
Feb 22, 2018

Second quadrant.

Explanation:

#-(11pi)/9 = -1((2pi)/9) = -pi - ((2pi)/9)#

#=> 2pi - pi - ((2pi)/9) = (7pi)/9#

Since #(7pi)/9 > pi/2#, it is in second quadrant.

Aliter : -(11pi)/9 = -((11pi)/9) * (360/2pi) = - 220^@#

#=> 360 - 220 = 140^@ = (90 + 50)^@#

It’s in second quadrant, as #140^@# is between #90^@# and #180^@#

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