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Answer 1 · 2018-02-15T14:57:10

molarity is moles of solute per liter of solution, determine number of moles, then convert to grams

$(2 L) \cdot \frac{(1 m o l g l u cos e)}{L} = 2 m o l g l u cos e$ $(2L)*((1mol glucose))/L = 2 mol glucose$

$(2 m o l) \cdot 180 \frac{g}{m o l} = 360 g$ $(2 mol )*180g/(mol) = 360 g$ glucose

Answer 2 · 2018-02-15T15:44:06

$360 g$ $360g$

Well, a $1 M$ $1M$ glucose solution means that it has a concentration of $1 m o l / L$ $1mol"/"L$ .

So, $2 L$ $2L$ of the glucose solution will contain a total of $2$ $2$ moles.

So, the total mass of the glucose will be

$2 m o l \cdot 180 g / m o l = 360 g$ $2mol*180g"/"mol=360g$