How do you factor #3b ^ { 2} - 48b + 189#?

2 Answers
Sahar Mulla ❤
Feb 15, 2018

#3b^2−48b+189#
taking 3 as a common factor.,

#3(b^2−16b+63 )#
#3(b^2−7b-9b+63 )#
#3(b(b−7)-9(b-7))#
#3(b−9)(b-7)#

Jim G.
Feb 15, 2018

#3(b-9)(b-7)#

Explanation:

#"take out a "color(blue)"common factor of 3"#

#rArr3(b^2-16b+63)larrcolor(blue)"factor the quadratic"#

#"the factors of + 63 which sum to - 16 are - 9 and - 7"#

#rArr3(b-9)(b-7)#

#rArr3b^2-48b+189=3(b-9)(b-7)#

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