Question #8d120

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Answer 1 · 2018-02-13T18:10:18

#x=sqrt(13)# or

#x~~3.60555128#

The equation is #x^2-2=11#.

First, isolate the #x# term.

#x^2color(red)(-2)=11color(red)(+2)#

#x^2=13#

Now, you take the square root of #x# to get rid of the square symbol.

#sqrt(x^2)=sqrt(13)#

#cancelsqrt(x)^cancel2=sqrt(13)#

#x=sqrt(13)#

Since you cannot simplify farther, then the answer is

#x=sqrt(13)# or

#x~~3.60555128#