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1 Answer
Victoria E.
Feb 12, 2018

Convert mass to moles, realize that ratio of ammonia to carbon dioxide is 2:1 so ammonia will be the limiting reactant. Since 2 moles of ammonia react with one mole of CO_2, (0.03742/2 = 0.1871) moles of CO_2 can be used, and 0.0724 moles of CO_2 will be left over.

Explanation:

((6.372 g) )/ (17.03(g/(mol))) = 0.3742mol NH_3

((11.42 g)) /(44.01(g/(mol)) = 0.02595 mol CO_2
Since 2 moles of ammonia react with one mole of CO_2, (0.03742/2 = 0.1871) moles of CO_2 can be used, and 0.0724 moles of CO_2 will be left over.

(0.0724 mol CO_2)(44.01g/(mol)) = 3.19 g left over CO_2

One mole of urea is formed for each mole of CO_2 consumed, so 0.1872 moles of urea will be produced.
(0.1872 (mol urea))(60.06 (g/(mol)))=11.24g urea produced

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