Question #82330

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Answer 1 · 2018-02-12T11:00:33

$2 sinx$

$(cosx divide cotx) + sinx$

We know , $cotx = cosx/sinx$

Put this value in the above equation

$(cosx divide cosx/sinx) + sinx$

$(cosx * sinx/cosx) + sinx$

$(cancel cosx * sinx/(cancel cosx)) + sinx$

$->sinx + sinx$

$->2 sinx$