Question #8cc77

1 Answer
MetaPhysik
Feb 11, 2018

58.5 kg

Explanation:

#K=1/2mv^2#

#mv^2=2K#

#m=(2K)/v^2#

#v=constant = average speed = (1xx10^2m)/(8.8s)#
#K= 3.3.99xx10^3#

Substitute these values into the m equation above,

#m=(2K)/v^2= (2*3.99xx10^3J)/((1xx10^2m)/(8.8s))^2=58.5 J/(m^2/s^2)= 58.5 (kg cancel(m^2//s^2))/cancel(m^2//s^2)=58.5 kg#

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