Question #216d6

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Answer 1 · 2018-02-11T18:00:55

$238 m//s$

$KE = 1/2mv^2$

where

$KE$ is kinetic energy in $J$

$m$ is mass in $kg$

$v$ is velocity in $m/s$

$49.0g = 0.049kg$

$1392J = 1/2 * 0.049 * v^2$

$0.049 * v^2 = 2784J$

$v^2 = 2784/0.049 = 2784000/49$

$v = sqrt(2784000/49) = 238$ (3s.f.)

speed $= 238m//s$ (3s.f.)