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  1. Two kids pull in opposite directions on a toy of mass 0.544 kg. One exerts a force of 67.6 N and the other 12.6 N. Both pull horizontally and friction is negliglble.
    (f) Calculate the net force in the x-direction. (g) Calculate the normal force.
    (h) Calculate the net force in the y-direction.

2 Answers
Jane
Feb 11, 2018

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From the free body diagram,we can say,

Net force acting horizontally, #(67.6-12.6)=55N# (along #X# axis)

As,the toy is not moving up or down,so it is at vertical equilibrium, So we can say #N=mg=0.544*10=5.44N# (#N# is the normal force)

So,net force along #Y# axis is zero.

MetaPhysik
Feb 11, 2018

55N, 0 or 5.33N, -5.33N or 0

Explanation:

Horizontal net force
#(f) F_"x net"= 67.6 -12.6 = 55N#.
The next force in the same direction of the stronger force.

#(g)# It depends. If the toy is not resting on anything, the normal force is zero. If it is resting on a desk or table while it is being pulled, then the desk pushes back with a normal force
#N- mg = 0, rArr N=mg =0.544 kg * 9.8 m/s^2=5.33N#

#(h)# If the toy is not resting on anything,

# F_"y net"=-mg = -5.33N#;

If the toy is resting on a desk, then # F_"ynet"= N-mg = 5.33N-5.33N=0#

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