How #H_2SO4+NaOH# could be #Na_2SO4+H_2O# and how to balance it?

2 Answers
Johnson Q.
Feb 11, 2018

It will be #H_2SO_4 + 2NaOH -> Na_2SO_4 + 2H_2O#

Explanation:

You begin with #H_2SO_4 + NaOH -> Na_2SO_4 + H_2O#.
Notice that there are 2 #Na#'s on the right side. This means you need to add a coefficient of 2 in front of #NaOH# to balance the #NA#'s. Now, you count the #H#'s. You'll find that there are 4 on the left and only 2 on the right. To balance the #H#'s, add a coefficient of 2 infront of #H_2O#.

Ujjwal
Feb 11, 2018

See the explanation

Explanation:

#H_2SO_4# is an acid while #NaOH# is a base.

An acid and a base react to give salt of the acid and water.

So, sulphuric acid (#H_2SO_4#) react with sodium hydroxide (#NaOH#) to give sodium sulphate
(#Na_2SO_4#) which is a salt and water.

This reaction is also called neutralization reaction.

For balancing it, there should be equal number of each atom on both the sides.

The balanced equation is:-

#H_2SO_4 + 2NaOH -> Na_2SO_4 + 2H_2O#

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