Question #045b1

1 Answer
tcw1
Feb 9, 2018

#2K_((s)) + Br_(2(l)) -> 2KBr_((s))#

Explanation:

First, identify the reactants and products. Note that bromine is a diatomic molecule in the liquid state. Potassium is in the solid state at room temperature.
#K_((s)) + Br_(2(l)) -> KBr#

Balance the equation:

#2K_((s)) + Br_(2(l)) -> 2KBr#

If you need to get technical, this reaction contains several other steps:
#K_((s))-> K_((g))#
#K_((g))-> K^(+) (g)#
#Br_(2(l)) -> 2Br_((g))#
#Br_((g)) -> Br^- (g)#
#K^+ (g) + Br^- (g) -> KBr_((g))#
#KBr_((g)) -> KBr_((l))#

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