Question #e2dc4

1 Answer
Cheez Pleez
Feb 7, 2018

Length: #x>=16#, Width: #y>=32#

Explanation:

I'm not understanding this too well, because there is no #x# variable mentioned above. Anyway, let's give it a try.

Since an area of a rectangle can't be negative, it has to be the absolute value of something. Let's try this.

#4x-64>=0#
#x>=16#

Since we found the length of the rectangle, the width would be #x+16>=32#.

Yay!

Related questions
Impact of this question
785 views around the world
You can reuse this answer
Creative Commons License