What is the three numbers in an arithmetic progression whose sum is 6 and product is -64?

1 Answer
Sahar Mulla ❤
Feb 4, 2018

Lets consider the 3 numbers in AP to be, x-d, x, x+d, where d is the common difference.

So, according to the question, their sum is 6
=> (x-d) +(x) +(x+d)=6
=>3x=6
=>x=2

and their product is -64;
=>(x-d)(x)(x+d)=-64
x(x^2-d^2) = -64
2(4-d^2)=-64
4-d^2=-32
d^2=4+32
d=sqrt36
d=6

So, the three numbers are, x-d, x, x+d
=>(2-6), (2), (2+6)
=>-4, 2,8

color(purple)(-Sahar)

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