What is the lowest common denominator of $\frac{3}{x^{3} y}$ $3/(x^3y)$ and $\frac{7}{x y^{4}}$ $7/(xy^4)$ ?

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What is the lowest common denominator of $\frac{3}{x^{3} y}$ $3/(x^3y)$ and $\frac{7}{x y^{4}}$ $7/(xy^4)$ ?

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Answer 1 · 2018-02-03T19:05:48

$x^{3} y^{4}$ $x^3y^4$

Explanation:

To find the lowest common denominator, you have to find the least common multiple of both denominators. $\frac{3}{x^{3} y}$ $3/(x^3y)$ has the denominator $x^{3} y$ $x^3y$ , and $\frac{7}{x y^{4}}$ $7/(xy^4)$ has $x y^{4}$ $xy^4$ . First, think of $x$ $x$ . you need to have $x^{3}$ $x^3$ as the $x$ $x$ part because $x$ $x$ goes into it $x^{2}$ $x^2$ times, and $x^{3}$ $x^3$ goes into it once. Do this again for the $y$ $y$ part: you need $y^{4}$ $y^4$ because $y^{4}$ $y^4$ goes in once and $y$ $y$ goes in $y^{3}$ $y^3$ times. Now combine your $x$ $x$ and $y$ $y$ parts. You end up with $x^{3} y^{4}$ $x^3y^4$ .

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What is the lowest common denominator of $\frac{3}{x^{3} y}$ $3/(x^3y)$ and $\frac{7}{x y^{4}}$ $7/(xy^4)$ ?

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