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Answer 1 · 2018-02-03T07:49:49

#-4+sqrt11#

We can multiply both terms of the fraction by the factor #2-sqrt(11)#, and transfer the radical form to the numerator:

#((3-2sqrt11)(2-sqrt11))/((2+sqrt11)(2-sqrt11))#

Let's multiply and expand the terms:

#(6-3sqrt11-4sqrt11+2sqrt11^2)/(4-sqrt11^2)#

that's

#(6-7sqrt11+22)/(4-11)#

#(28-7sqrt11)/-7#

or, in standard form:

#-4+sqrt11#