3.01e22 Ag+ ions is present in? options a) 85 grams of AgNO3 b) 0.85g AgNO3 c) 8.5g AgNO3 d) 18.5g AgNO3

1 Answer
Sarita Rana · Nam D. · Soumalya Pramanik
Feb 2, 2018

8.5 g of AgNO_3

Explanation:

1 mole = 6.023 xx 10^23 ions
Ag^+ = 3.01 xx 10^22 ions

No. of moles of Ag^+ = (3.01 x 10^22 ions)/( 6.023 xx 10^23 ions) =

0.0499 moles

Molar mass of AgNO_3 = 169.87 g"/"mol

Mass of AgNO_3 = 0.0499 moles xx 169.87 g"/"mol = 8.47 g

AgNO_3 -> Ag^+ \ + \ NO_3^-

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