Question #55b04

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Question #55b04

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Answer 1 · 2018-02-02T08:36:41

Please read below;

Explanation:

The element is selenium $(S e)$ $(Se)$

It has atomic number of $34$ $34$

Its electronic configuration is $[A r] 3 d^{10} 4 s^{2} 4 p^{4} or 4 s^{2} 3 d^{10} 4 s^{2} 4 p^{4}$ $[Ar] 3d^10 4s^2 4p^4 or 4s^2 3d^10 4s^2 4p^4$

Electron per shell is $2, 8, 18, 6$ $2,8,18,6$

Therefore, It need to gain two electrons $(2 e^{-})$ $(2e^-)$ to attain the octet structure or be stable..

Answer 2 · 2018-02-02T10:00:13

$The element is located in Period 4 and in Group 16$ $"The element is located in Period 4 and in Group 16"$ $and it is identified as Selenium(Se) .$ $"and it is identified as Selenium(Se)".$ $This element will gain 2 more electrons to achieve stability.$ $"This element will gain 2 more electrons to achieve stability."$

Explanation:

The highest energy level is 4 which means that the element is located in $Period 4$ $"Period " 4$ and that the valence electron is 6; that is, $2 e^{-}$ $2e^-$ in the $s sublevel$ $s " sublevel"$ and $4 e^{-}$ $4e^-$ in $p sublevel$ $p " sublevel"$ . which means that the element is in $Group 16$ $"Group " 16$

Using the periodic table, this element is identified as $Selenium (S e)$ $"Selenium" (Se)$

Since the element is a nonmetal; the tendency is to gain $2 e^{-}$ $2e^-$ to complete an octet and achieve stability.

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Question #55b04

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