Question #311ad

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Question #311ad

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Answer 1 · 2018-02-02T04:21:02

$30.61 C$ $30.61C$

Explanation:

Ideal gas law density, $D = \frac{P M}{R T}$ $D= (PM)/(RT)$

Where, $D$ $D$ = density of gas = $10.3$ $10.3$ g/L
$P$ $P$ = Pressure of gas = $6.43$ $6.43$ atm
$M$ $M$ = Molar mass of gas = $39.948$ $39.948$ grams/mole
$R$ $R$ = Gas Law constant = $0.0821$ $0.0821$ Latm/mol K
$T$ $T$ = Temperature of gas =?

$10.3 = \frac{6.43 \times 39.948}{0.0821 \times T}$ $10.3 = (6.43xx39.948)/(0.0821 xx T)$

or, T = 303.76K = $30.61 C$ $30.61C$

Note: $0 K = - 273.15$ $0K = -273.15$ C so subtract this value from the Kelvin value got above to get Celsius value

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Question #311ad

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