Question #8a90d

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Question #8a90d

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Answer 1 · 2018-02-01T23:44:51

write a balanced equation
convert g of water to moles, convert T to Kelvin
use stoichiometry to calculate number of moles of hydrogen formed
use combined gas law or ideal gas law to solve for V

Explanation:

$2 H_{2} O \to 2 H_{2} + O_{2}$ $2H_2O rarr2H_2 + O_2$

$\frac{10 g H_{2} O}{18.01 (\frac{g}{m o l})} = 0.556 m o l$ $(10 g H_2O)/(18.01(g/(mol)) )= 0.556mol$

Since water and hydrogen have a 1:1 molar ratio
0.556 mol of $H_{2}$ $H_2$ will be formed
$P V = n R T$ $PV = nRT$

$V = n R \frac{T}{P}$ $V= nRT/P$

$V = (0.556 m o l) (0.082057 L \cdot a t m / K \cdot m o l) (305 K) / 0.940 a t m$ $V= (0.556mol)(0.082057L*atm//K*mol)(305K)//0.940atm$
$V = 14.8 L$ $V= 14.8L$

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Question #8a90d

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