Question #02f6e

1 Answer
Jarni Renz
Feb 1, 2018

#="60.15g " MgSO_4#

Explanation:

  1. Find the molar mass of #MgSO_4# which relative atomic masses of elements constituting the compound is obtainable in the periodic table.
    #=120" g/mol"#
  2. Given the concentration of the solution, and the assumed volume, the number of moles #(eta)# of the solute can be computed as described below;
    #M=eta/V#; rearrange formula and isolate #eta#
    #eta=MxxV#

#where:#

#M=Molarity=0.5M=0.5" mol/L"#
#V=Volume=1L#

#eta=MV#
#eta=(0.5mol)/cancel((L))xx1cancel(L)#
#eta=0.5molMgSO_4#

  1. Now, use the molar mass of the compound to find the mass of the solute; i.e.,
    #=0.5molcancel(MgSO_4)xx(120.3gMgSO_4)/(1cancel(molMgSO_4))#
    #=60.15gMgSO_4#
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