A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 657 m/s. The gun is pointed directly at the center of the bull's-eye......?

Question

A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 657 m/s. The gun is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.020 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

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Answer 1 · 2018-01-31T20:58:13

#"please have a look at the solution below."#

enter image source here

#BC=y=1/2 g t^2#

#0.02=1/2*9.81*t^2#

#t^2=(2*0.02)/(9.81)#

#t^2=(0.04)/(9.81)#

#sqrt(t^2)=sqrt((0.04)/(9.81))#

#t=0.02" "sec#

#AB=v*t#

#AB=657*0.02=13.14" "meters.#