How do you solve $\frac{1}{12} (48 + 24 b) = 2 (17 - 4 b)$ $\frac { 1} { 12} ( 48+ 24b) = 2( 17- 4b )$ ?

Question

1319 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-31T11:51:57

$\frac{1}{12} (48 + 24 b) = 2 (17 - 4 b)$ $1/12(48+24b)=2(17−4b)$

$(\frac{48}{12} + \frac{24 b}{12}) = 2 \cdot 17 - 2 \cdot 4 b$ $(48/12+(24b)/12)=2*17−2*4b$

$4 + 2 b = 34 - 8 b$ $4+2b=34−8b$

$2 b + 8 b = 34 - 4$ $2b+8b=34-4$

$10 b = 30$ $10b=30$

$b = 3$ $b=3$

-Sahar.

How do you solve \frac { 1} { 12} ( 48+ 24b) = 2( 17- 4b )112(48+24b)=2(17−4b)\frac { 1} { 12} ( 48+ 24b) = 2( 17- 4b )?