How many atoms are contained in 0.10 grams of copper?

1 Answer
Dwight
Jan 29, 2018

This is #9.47xx10^(20)# atoms.

Explanation:

The mass of one mole of copper is 63.55 g. So, 0.10 g is equal to

#0.10 g -: 63.55 g/"mol" = 0.001574 "mol"#

Next, we convert moles into # of atoms, using Avogadro's number:

#0.001574 xx 6.02xx10^(23) = 9.47xx10^(20)# atoms

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