Question #9773c

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Question #9773c

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Answer 1 · 2018-01-28T07:34:01

(See solution process below)

Explanation:

We will prove this showing that $L . H . S = R . H . S$ $L.H.S=R.H.S$
Consider $L . H . S :$ $L.H.S:$
$4 sin Q cos Q = 2 [2 sin Q cos Q] = 2 sin 2 Q$ $4sinQcosQ=2[2sinQcosQ]=2sin2Q$
Hence we get the $L . H . S . = 2 sin 2 Q$ $L.H.S.= 2sin2Q$
Now consider $R . H . S .$ $R.H.S.$
$\frac{sin 4 Q}{cos 2 Q} \Rightarrow \frac{sin 2 (2 Q)}{cos 2 Q}$ $(sin4Q)/(cos2Q)rArr[sin2(2Q)]/[cos2Q]$ $\Rightarrow \frac{2 sin 2 Q cos 2 Q}{cos 2 Q}$ $rArr[2sin2Qcos2Q]/[cos2Q]$ $\Rightarrow 2 sin 2 Q$ $rArr2sin2Q$
Hence $R . H . S = 2 sin 2 Q$ $R.H.S=2sin2Q$
$:.R.H.S=L.H.S$

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Question #9773c

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