Question #8284d

1 Answer
MetaPhysik
Jan 27, 2018

4.0 m/s

Explanation:

Use the kinematic equations or use the definitions of acceleration and velocity to derive the kinematic equation blow.

A) #Deltax= v_0t+1/2at^2#
#v_0= 0 larr#starting from rest, and the clock is reset to zero.

#t = sqrt((2Deltax)/a)= 4.0 hrs #

The answer is assuming that # a = (3km)/(hr^2# because the time unit is left blank in the question.

B.) Derive the equation from the de
# a = (dv)/dt and v= dx/dt#

Given the a = constant and initially #t=0, v(0)=v_0, x(0)=x_0#
From # a = (dv)/dt#, and take the antiderivative,
# int_(0)^tadt= v - v_0 #

#rArrv= v_0 + at#
Because # v=(dx)/dt#
#rArr dx/dt= v_0 + at#
Take the antiderivative to get
#Deltax =v_0t + 1/2at^2 #
which is just the kinematic equation used above.

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