Question #9ed21

1 Answer
Jane
Jan 25, 2018

#65 m/s#

Explanation:

Suppose,the ball was projected vertically with velocity #u#

So,distance(#s#) covered in #5th# second is #u- 1/2g(2*5-1)#

and, in #6th# second is #u-1/2g(2*6-1) = (h)#

Now,given,, #s=2h#

So, equating the obtained equations,we get, #u=(13g)/2#

Now,if #g= 10 m/s^2# ,then #u=65m/s#

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