Question #5230c

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Answer 1 · 2018-01-25T15:04:18

7.2 $mu$ m.

The photon energy $E_gamma$ is related to the corresponding light wavelength $lambda$ by

$E_gamma = (hc)/lambda$ ,

where $h$ and $c$ are the Planck's constant and the speed of light in vacuum, respectively.

In this case, $E_gamma = 2.754 * 10^20 J$ , then:

$2.754 * 10^20 = (6.6 * 10^-34 * 3 * 10^8)/lambda$ ;

$lambda = (19.8 * 10^-26)/(2.754 * 10^20)$ .

This yields, approximately:

$lambda = 7.2 * 10^-6 m$ .