How do you multiply 4n ^ { 0} \cdot 4m ^ { - 3} n ^ { - 1}?

2 Answers
Nam D.
Jan 25, 2018

4m^-3n^-1

Explanation:

Well, know that n^0=1 for all ninRR, n!=0.

:.4n^0=4

:.4n^0*4m^-3*n^-1=4*4m^-3n^-1

The only like-terms left are the whole numbers, so we multiply them. (4*4=16)

=16m^-3n^-1

Radioactive Teddybear
Jan 25, 2018

16/(m^3n)

Explanation:

Everything in this is multiplied since there's no addition or subtraction or division symbol.
So
1, 4 times 4 is 16
2. Anything to the power of 0 is 1, so you just kind of discard that thing since anything times 1 doesn't change.
3. Anything to the negative power just means that it is one over the thing, so m^-3 becomes 1/m^3

Put everything together, and you'll get the answer

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