Question #42b7a

1 Answer
Jarni Renz
Jan 20, 2018

#~~3.11xx10^2ml#

Explanation:

First thing to do here is to find the mass of water by subtracting the mass of the empty flask from the mass of the flask with the water; that is,

# 568.6g="mass flask+water"#
#-#
#ul(257.7g)="mass of empty flask"#
#310.9g="mass of water"#

Kwowing the mass of the water and the density as provided, the volume of the water inside the flask can be calculated through the formula shown below. Rearrange formula to isolate the needed variable; the volume.

#rho=(mass(m))/(volume(V))#
#V=m/rho#

where:

#rho=(1.00g)/(ml)#
#m=310.9g#

#V=(310.9cancel(g))/((1.00cancel(g))/(ml))#
#V~~311ml#

If expressed in standard scientific notation, this can be written as
#color(red)(3.11xx10^2ml)#. Remember that the standard scientific notation follows the format as shown below.

#Mxx10^n#

where:

#1<=M<10 " and n is an integer"#.

Another pointer to remember is that moving the decimal point to the left corresponds to a positive exponent. The mnemonic LIP, (Left Is Positive) will help you remember this when writing scientific notations.

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