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Question #dc355

1 Answer

Jan 19, 2018

#y'=10tan^4(x)sec^2(x)#

Explanation:

Given: #2tan^5(x)#

Via the chain rule: ##

#y'=d/dx=2d/dx(tan(x))^5*d/dx(tan(x))#

#y'=d/dx=2*5(tan(x))^4*sec^2(x)#

#y'=d/dx=10tan^4(x)sec^2(x)#

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