Question #0e707

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Answer 1 · 2018-01-19T01:38:57

The helium neon laser typically operates at $632.8$ $nm.$

Thus the energy contained in a single photon from the laser is:

$E=hf=hc/lambda=(6.63times10^(-34))(3times10^8)/(632.8times10^(-9))$

$=3.143times10^(-19)J$

If the laser operates at $90$ $wa t t=90$ $Js^-1$ then the amount photons emitted per second will be:

Power output of laser/ Energy of photon.

$=90/(3.143times10^(-19))=2.863times10^20$ $s^-1$