Question #0e707

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Question #0e707

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Answer 1 · 2018-01-19T01:38:57

The helium neon laser typically operates at $632.8$ $632.8$ $n m .$ $nm.$

Thus the energy contained in a single photon from the laser is:

$E = h f = h \frac{c}{λ} = (6.63 \times 10^{- 34}) \frac{3 \times 10^{8}}{632.8 \times 10^{- 9}}$ $E=hf=hc/lambda=(6.63times10^(-34))(3times10^8)/(632.8times10^(-9))$

$= 3.143 \times 10^{- 19} J$ $=3.143times10^(-19)J$

If the laser operates at $90$ $90$ $w a t t = 90$ $wa t t=90$ $J s^{- 1}$ $Js^-1$ then the amount photons emitted per second will be:

Power output of laser/ Energy of photon.

$= \frac{90}{3.143 \times 10^{- 19}} = 2.863 \times 10^{20}$ $=90/(3.143times10^(-19))=2.863times10^20$ $s^{- 1}$ $s^-1$

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