Question #d27c7

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Answer 1 · 2018-01-18T17:19:10

OK, we can work this out.

If #y = 20 and x = 8# then as #20 = 2.5xx8# so #y = 2.5xx x#

Let’s use that to find y if x = 76, knowing that y is always two and a half times bigger than x.

#y = 2.5xx76 = 190#

Answer 2 · 2018-01-20T01:01:53

#y=190#

Set up a proportion.

#8/20=76/y#

Cross multiply.
Multiply each numerator by the opposite denominator.

#(8xxy)=(76xx20)#

Simplify.

#8y=1520#

Divide both sides by #8#.

#(8y)/8=1520/8#

Cancel #8# on the left-hand side.

#(color(red)cancel(color(black)(8))^1y)/color(red)cancel(color(black)(8))^1=1520/8#

Simplify.

#y=190#