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Answer 1 · 2018-01-18T01:53:58

$y = 5 x - 2$ $y=5x-2$

We know that the linear equation is in the form of

$y = m x + b$ $y=mx+b$ , $m$ $m$ is the slope $,$ $,$ b# is the y-intercept

Given: $m = 5$ $m=5$ , passes through $(3, 13)$ $(3,13)$

$:.y=5x+b$

We also know that it passes through $(3,13)$ , so we can plug that in for $x=3, y=13$

$13=5*3+b$

$13=15+b$

$b=-2$

$:. y = 5x-2$

Answer 2 · 2018-01-18T01:59:20

In point-slope form: $y-13=5(x-3)$

In $y=mx+b$ form: $y=5x-2$

We can use the point-slope formula to find the equation of the line

$y-y_1=m(x-x_1)$

Where $m$ is the slope and $(x_1,y_1)$ is a point on the line

Given: $m=5$ and $(x_1,y_1)->(3,13)$

$y-13=5(x-3)$

This is the equation in point-slope form but this can be rewritten in $y=mx+b$ form

To do that, we'll solve the above equation for $y$

$y-13=5x-15$

$y-13color(red)(+13)=5x-15color(red)(+13)$

$y-0=5x-2$

$y=5x-2$

The graph of the line is shown below:

graph{5x-2 [-10, 10, -5, 5]}