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How do you solve #3^ { 7x } = 3.3#?

1 Answer

Jan 16, 2018

#x = 1/7log_3 3.3#

Explanation:

#3^(7x)=3.3#

Take log to the base 3 of both sides:

#log_3 3^(7x)=log_3 3.3#

Use the rules of logs:

#-> 7x log_3 3=log_3 3.3#
#-> 7x= log_3 3.3#
#therefore x = 1/7log_3 3.3#

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