How do you solve $10 = 3 (r + 1) + 1$ $10=3( r + 1) + 1$ ?

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How do you solve $10 = 3 (r + 1) + 1$ $10=3( r + 1) + 1$ ?

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Answer 1 · 2018-01-16T18:00:30

r=2

Explanation:

$10 = 3 (r + 1) + 1$ $10=3(r+1)+1$
$10 = 3 r + 3 + 1$ $10=3r+3+1$
$10 = 3 r + 4 / - 4,$ $10=3r+4 // -4,$

$6 = 3 r / : 3,$ $6=3r //:3,$

$\Rightarrow r = 2$ $rArrr=2$

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Answer 2 · 2018-01-16T18:02:21

$r = 2$ $r = 2$

Explanation:

$10 = 3 (r + 1) + 1$ $10 = 3(r+1)+1$

subtract $1$ $1$ :

$9 = 3 (r + 1)$ $9 = 3(r+1)$

divide by $3$ $3$ :

$3 = r + 1$ $3 = r+1$

$r + 1 = 3$ $r+1 = 3$

subtract $1$ $1$ :

$r = 2$ $r = 2$

alternatively:

expand brackets:
$10 = 3 r + 3 + 1$ $10 = 3r + 3 + 1$

collect like terms:

$10 = 3 r + 4$ $10 = 3r+4$

subtract $4$ $4$ :

$3 r = 6$ $3r = 6$

divide by $3$ $3$ :

$r = 2$ $r = 2$

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How do you solve $10 = 3 (r + 1) + 1$ $10=3( r + 1) + 1$ ?

2 Answers

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