If $s (x) = x - 7$ $s(x)=x-7$ and $f (x) = 4 x^{2} - x + 3$ $f(x)=4x^2-x+3$ , what is $(t \cdot s) (x)$ $(t*s)(x)$ ?

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If $s (x) = x - 7$ $s(x)=x-7$ and $f (x) = 4 x^{2} - x + 3$ $f(x)=4x^2-x+3$ , what is $(t \cdot s) (x)$ $(t*s)(x)$ ?

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Answer 1 · 2018-01-15T20:56:10

$4 x^{2} - 57 x + 202$ $4x^2-57x+202$

Explanation:

Plug $s (x)$ $s(x)$ into $t (x)$ $t(x)$ where you would normally put an $x$ $x$ value
$4 {(x - 7)}^{2} - (x - 7) + 3$ $4(x-7)^2-(x-7)+3$
Distribute to get $4 (x^{2} - 14 x + 48) - x + 7 + 3$ $4(x^2-14x+48)-x+7+3$
Continue distributing to get $4 x^{2} - 56 x + 192 - x + 7 + 3$ $4x^2-56x+192-x+7+3$
Combine like terms to get $4 x^{2} - 57 x + 202$ $4x^2-57x+202$

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If $s (x) = x - 7$ $s(x)=x-7$ and $f (x) = 4 x^{2} - x + 3$ $f(x)=4x^2-x+3$ , what is $(t \cdot s) (x)$ $(t*s)(x)$ ?

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If s(x)=x−7s(x)=x-7 and f(x)=4x2−x+3f(x)=4x^2-x+3, what is (t⋅s)(x)(t*s)(x)?

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If $s (x) = x - 7$ $s(x)=x-7$ and $f (x) = 4 x^{2} - x + 3$ $f(x)=4x^2-x+3$ , what is $(t \cdot s) (x)$ $(t*s)(x)$ ?